benedict52 benedict52

11-09-2020
Chemistry

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how many atom will be present in2.7 g of aluminumal=22 na=6.02×^23

Respuesta :

mario200000 mario200000

11-09-2020

Answer:

just add ⅜⁸ and ⅖⁵

Explanation:

because I was told it awnsers almost all questions

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