Answer:
It is a perfect cube with sides of 5.
Step-by-step explanation:
If 125 was a perfect square, there would be a whole number A which, squared, would give us 125.
[tex]A^2 = 125\\A = \pm 11.18...[/tex]
We can see that the roots are not whole numbers.
(Tip: without a calculator, we can find this by testing [tex]10^2 \ 11^2\ 12^2[/tex] to see if any give us 125. We get 100, 121, 144 respectively. None of them is 125.)
If it was a perfect cube, there would be a whole number B which, cubed, would give us 125.
[tex]B^3 = 125\\B = \sqrt[3]{125} \\B = 5[/tex]
As we can see, there IS a whole number B: 5 !
(Without a calculator, like the previous one, we could try [tex]4^3\ 5^3\ 6^3[/tex] and we'd find that [tex]5^3[/tex] = 125)
Answer: It is a perfect cube with sides of 5.
