Answer:
[tex]B = \frac{6D + 18 {f}^{3} }{M} [/tex]
Step-by-step explanation:
[tex] - 3 {f}^{3} + \frac{1}{6} MB = D [/tex]
Multiply through by 6 to eliminate the fraction
That's
[tex] - 18 {f}^{3} + MB = 6D[/tex]
Move - 18f³ to the right side of the equation
That's
[tex]MB = 6D + 18 {f}^{3} [/tex]
Divide both sides by M to make B stand alone
That's
[tex] \frac{MB}{M} = \frac{6D + 18 {f}^{3} }{M} [/tex]
We have the final answer as
[tex]B = \frac{6D + 18 {f}^{3} }{M} [/tex]
Hope this helps you
