AsF₃:
M=132g/mol
m=150g
n = m/M = 150g/132g/mol = 1,14mol
CCl₄:
M=154g/mol
m=180g
n = m/M = 180g/154g/mol = 1,17mol
2AsF₃ + 3CCl₄ ⇒ 2AsCl₃ + 3CCl₂F₂
2mol : 3mol : 3mol
1,14mol : 1,17mol : 1,17mol
limiting reagent
0,78mol will react
CCl₂F₂:
n = 1,17mol
M = 121g/mol
m = nM = 1,17mol * 121g/mol = 141,57g
Answer a