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The length of a rectangle is 5 centimeters longer than twice its width. If the perimeter of the rectangle is 88 centimeters, what is the width?

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Answer:

The length of a rectangle is 5 centimetres longer than twice its width. If the perimeter of the rectangle is 88 centimetres, what is the width?

width=x

length=2x+5

perimeter=88=2L+2W

 

so half perimeter=44=L+W

x+2x+5=44

3x=39

x=13 cm width ANSWER

2x+5=31 cm length

Lanuel

The width of the rectangle is Width, W = 13 centimeters.

  • Let the length of the rectangle be L.
  • Let the width of the rectangle be W.

Given the following data:

  • Perimeter of rectangle = 88 centimeters

Translating the word problem into an algebraic equation, we have;

[tex]L = 2W + 5[/tex]

To find the width of the rectangle;

Mathematically, the perimeter of a rectangle is given by the formula;

[tex]P = 2(L + W)[/tex]

Substituting the values into the formula, we have;

[tex]88 = 2(2W + 5 + W)\\\\88 = 2(3W + 5)\\\\88 = 6W + 10\\\\6W = 88 - 10\\6W = 78\\\\W = \frac{78}{6}[/tex]

Width, W = 13 centimeters.

Therefore, the width of the rectangle is Width, W = 13 centimeters.

Find more information: brainly.com/question/897975

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