I need help on this mathematical equation B is the Midpoint of AC.

Answer:
[tex]x=2[/tex]
Step-by-step explanation:
B is the midpoint of AC so AB = BC.
AB + BC = AC
AB + AB = AC
2(AB) = AC
[tex]2\left(3\left(3x-1\right)\right)=5\left(2x+2\right)[/tex]
Expand:
[tex]2\times3\left(3x-1\right)=5(2x+2)[/tex]
[tex]6\left(3x-1\right)=5(2x+2)[/tex]
[tex]6\times3x-6\times1=5\times2x+5\times2[/tex]
[tex]18x-6=10x+10[/tex]
Add 6 to both sides:
[tex]18x-6+6=10x+10+6[/tex]
[tex]18x=10x+16[/tex]
Subtract 10x from both sides:
[tex]18x-10x=10x+16-10x[/tex]
[tex]8x=16[/tex]
Divide both sides by 8:
[tex]\frac{8x}{8}=\frac{16}{8}[/tex]
[tex]x=2[/tex]
Answer:
[tex]x=2[/tex]
Step-by-step explanation:
First, we know that the entire segment adds up to 5(2x+2). In other words:
[tex]AB+BC=5(2x+2)[/tex]
Now, since B is the midpoint of AC, by the definition of midpoint, AB and BC are equivalent. So:
[tex]AB=BC[/tex]
Since we know that, let's substitute BC for AB in the first equation:
[tex]AB+BC=5(2x+2)\\[/tex]
This is equivalent to:
[tex]AB+AB=5(2x+2)[/tex]
Combine like terms:
[tex]2AB=5(2x+2)[/tex]
And since we know that AB is 3(3x-1), substitute:
[tex]2(3(3x-1))=5(2x+2)[/tex]
Now, solve for x.
Distribute the left side:
[tex]6(3x-1)=5(2x+2)[/tex]
Distribute both sides:
[tex]18x-6=10x+10[/tex]
Add 6 to both sides:
[tex]18x=10x+16[/tex]
Subtract 10x from both sides:
[tex]8x=16[/tex]
Divide both sides by 8:
[tex]x=2[/tex]
So, the value of x is 2.
And we're done!
Notes:
You didn't particularly state what you need to find. If you want to length of AB or BC, it would be:
[tex]AB=BC=3(3(2)-1)=15[/tex]
And the entire length AC is:
[tex]AC=2(15)=30[/tex]