The value of f(g(x)) is, [tex]f(g(x))=3x^{2} -24x+50[/tex]
The given function are,
[tex]f(x)=3x^{2} +6x+5\\\\g(x)=-x+3[/tex]
We have to find [tex]f(g(x))[/tex].
[tex]f(g(x))=f(-x+3)=3(-x+3)^{2}+6(-x+3)+5\\ \\f(g(x))=3(x^{2} +9-6x)-6x+18+5\\\\f(g(x))=3x^{2} +27-18x-6x+23\\\\f(g(x))=3x^{2} -24x+50[/tex]
Thus, the value of [tex]f(g(x))=3x^{2} -24x+50[/tex]
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