Answer:
B) CH3CH2CH2F
Explanation:
All the other compounds listed among the options are capable of forming hydrogen bonds with water except CH3CH2CH2F.
Recall that hydrogen bonds are formed when hydrogen is directly bonded to a highly electronegative atom such as nitrogen, oxygen, fluorine, sulphur, et cetra.
Such bonds are not present in CH3CH2CH2F, rather fluorine is bonded to carbon to give a halogenoalkane. This compound will display the least solubility in water.
The one compound among the given options that is least soluble in water is;
Option B; CH₃CH₂CH₂F
We know in chemistry that hydrogen bonding affects solubility in that the presence of hydrogen bonding between the molecules of a substance show us that such molecules are polar. This therefore means that the molecules will be soluble in a polar solvent such as water.
Looking at the options, all of them form hydrogen bonds except for Option B which has Fluorine (F) alone not directly bonded to hydrogen. Instead the fluorine will be bonded to a carbon atom which means it is not going to be easily soluble in water.
In conclusion, the one compound that would be the least soluble in water is CH3CH2CH2F.
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