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A circle is described by the equation x2 + y2 + 14x + 2y + 14 = 0. What are the coordinates for the center of the circle and the length of the radius?
(-7, -1), 36 units


(7, 1), 36 units


(7, 1), 6 units


(-7, -1), 6 units

Respuesta :

meerkat18
we are given the expression of the equation of a circle that is x2 + y2 + 14x + 2y + 14 = 0. Using ocmpleting the squares: 
x2 + y2 + 14x + 2y + 14 = 0(x+7)^2 + (y+1) ^2 = -14 + 49 + 1(x+7)^2 + (y+1) ^2 = 36 center thus is at (-7,-1) and the radius is equal ot square root of 36 equal to 6. 
abidemiokin

The coordinates for the center of the circle and the length of the radius are (-7, -1) and 6units

Equation of a circle

The standard equation of a circle is expressed as:

x² + y² +2gx + 2fy + C= 0

where

(-g, -f) is the centre

radius = √g²+f²-C

Given the following equation

x² + y² + 14x + 2y + 14 = 0

2gx =14x

g = 7

2fy = 2y

f = 1

The centre will be at (-7, -1)

radius = √49 + 1 -14

radius = √36 = 6 units

Hence the coordinates for the center of the circle and the length of the radius are (-7, -1) and 6units

Learn more on circle here; https://brainly.com/question/26594685

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