Respuesta :
Solution:
1. Rome
Minimum=0
Maximum=16
[tex]Q_{1}=3, Q_{3}=13, {\text{IQR}=Q_{3}-Q_{1}=13-3=10,[/tex]
Median ,[tex]Q_{2}=8.5[/tex]
Mean = 8
Standard Deviation(σ)=5.4
As, difference between , Maximum -Mean =Mean - Minimum=8
So, Mean will Worthy description to find the center of Data set, given about Rome.
2. New York
Minimum=1
Maximum=20
[tex]Q_{1}=4.5, Q_{3}=6, {\text{IQR}=Q_{3}-Q_{1}=6-4.5=1.5,[/tex]
Median ,[tex]Q_{2}=5.5[/tex]
Mean = 7.25
Standard Deviation(σ)=6.1
As, for New york , Mean is not the mid value, that is difference between Mean and Minimum is not same as Maximum and Mean.
As, you can see , the three Quartiles , [tex]Q_{1},Q_{2},Q_{3}[/tex] are very close to each other, it means , other data values are quite apart from each other. So, Mean will not appropriately describe the given data.So, in this case Median will suitable to find the center.
Option (B): The Rome data center is best described by the mean. The New York data center is best described by the median.
Answer: Option (B): The Rome data center is best described by the mean. The New York data center is best described by the median.
Step-by-step explanation: