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Work Shown:
x = number of plates Bull 1 broke
y = number of plates Bull 2 broke
z = number of plates Bull 3 broke
y = x+6 because the second bull broke 6 more plates compared to the first
z = y+4 since the third bull broke 4 more plates compared to the second
They all broke a combined 58 plates, meaning,
x+y+z = 58
Replace z with y+4 to get
x+y+z = 58
x+y+y+4 = 58
x+2y+4 = 58
Then replace y with x+6
x+2y+4 = 58
x+2(x+6)+4 = 58
From here solve for x
x+2(x+6)+4 = 58
x+2x+12+4 = 58
3x+16 = 58
3x = 58-16
3x = 42
x = 42/3
x = 14
Bull 1 broke 14 plates
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If you want to find out how many plates the other bulls broke, then use that x value to find y and z
y = x+6 = 14+6 = 20
Bull 2 broke 20 plates
z = y+4 = 20+4 = 24
Bull 3 broke 24 plates
Overall, they broke 14+20+24 = 58 plates in total, which matches the total given in the instructions. The answer has been confirmed.
Answer:
B1 = 14 plates broken
Step-by-step explanation:
Method 1
We start with (58 - 6- 4) = (58 - 10) = 48
= 48 : We prove 6+4 = 10
To find who has the fewest plates we can now try again
with 48-6 = 42 or 48-4 = 44
42/3 = 14
We add 6 = 20
We add 4 = 24
We get 14+ 20 +24 = 58 broken plates.
So we know starting with -6 gets us our answer and our order correct.
Method 2 ; We deduct the difference from the total to find B1 distribution
B1 = 14 so 58-6 is 52 (-10)
We divide 42/3
To get 14
Conclusion;
We find method 1 shows us
B1 = 48 B2 = 48 (+6) =54 B3 = 54(+4) = 58
And try now for (14 + 14 + 6 ) + ( 22 + 4)
= 14 + 20 + 24 = 58 broken plates.
