Angle Angle AA similarity postulate states that two triangles are similar if
two angles in one of the triangles are congruent (equal) to two angles in the
other triangle
The correct option for the method and additional information that would
prove triangle ONP and triangle MNL similar by AA similarity postulate is
option B.
B. Use rigid transformation to prove that angle NPO is congruent to angle NLM
The reason for arriving at the above selection is as follows;
The known parameter in triangle ΔONP and ΔMNL are;
Lines MO and LP intersect at vertex point N.
The angles on opposite side of the point N (either side of the X shape
formed by the two lines) which are ∠ONP and ∠LNM are vertically opposite
angles or opposite angles.
According to vertically opposite angles theorem ∠ONP and ∠LNM, which
are vertically opposite angles are congruent, and we can write.
∠ONP ≅ ∠LNM
The required parameter;
To find the additional information that would prove ΔONP and ΔMNL by
AA (Angle-Angle) similarity postulate.
Strategy;
Given that from the drawing, one (vertex) angle in one triangle is congruent
to one (vertex) angle in the other triangle, that is ∠ONP ≅ ∠LNM, it is
required to prove that one other angle in triangle ΔONP is congruent to a
corresponding angle in triangle ΔMNL.
Solution;
Prove that either ∠NPO or ∠NOP in ΔONP are congruent to ∠NLM or
∠NML respectively in ΔMNL by performing rigid transformations
(transformations that does not change shape) on either ΔONP or ΔMNL
including;
- Rotating triangle ΔONP by 180° with origin at point N, to form the image ΔO'N'P'.
- Translating the vertex point P' in the image ΔO'N'P', to the location of the point L in ΔMNL, and verify that the segments LN and LM in ΔMNL coincide with the segments P'N' and P'O' respectively of triangle ΔO'N'P'.
Therefore, the correct option is option B. Use rigid transformation to prove
that angle NPO is congruent to angle NLM.
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