Answer:
The answer is
[tex] {8.y}^{12} [/tex]
Step-by-step explanation:
(2y⁴)³
Using the rules of indices
That's
[tex]( {ax})^{b} = {a}^{b} . {x}^{b} [/tex]
So for the above expression we have
[tex]( {2y^{4} })^{3} = {2}^{3} . {y}^{4 \times 3} [/tex]
Simplify
We have the final answer as
8.y¹²
Hope this helps you
