Answer:
A
[tex]\epsilon_{max} = 0.774 \ V[/tex]
B
[tex]wt = 0^o[/tex]
Explanation:
From the question we are told that
The length of the side is [tex]l = 16.0 \ cm = 0.16 \ m[/tex]
The number of turns is [tex]N = 29 \ turns[/tex]
The magnetic field is [tex]B = 83.0 mT = 83 *10^{-3} \ T[/tex]
The angular speed is [tex]w = 1.20 * 10^2 rev/min = \frac{1.20 *10^2 * 2\pi}{60 } = 12.6 \ rad/s[/tex]
Generally the area is [tex]A = l^2[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon = N * w * B * A * cos(wt)[/tex]
At maximum [tex]cos(wt) = 1[/tex]
So
[tex]\epsilon_{max} = N * w * B * A[/tex]
[tex]\epsilon_{max} = 29 * 12.6 * 83*10^{-3}* (l^2)[/tex]
=> [tex]\epsilon_{max} = 29 * 12.6 * 83*10^{-3}* ((0.16)^2)[/tex]
=> [tex]\epsilon_{max} = 0.774 \ V[/tex]
At maximum emf
[tex]cos (wt) = 1[/tex]
=> [tex](wt) = cos^{-1} (1)[/tex]
=> [tex]wt = 0^o[/tex]
