A sprinter is running a 100m sprint race. The race begins, and stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, What was the sprinter's average velocity between the two time marks? Show all your work.

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sand75

Answer:

velocity = 7.7558 m/s

Explanation:

s = u × t

s - distance u - velocity t - time

59 - 12 = (7.98 - 1.92) *u

47 = ( 6.06) u

u = 7.7558 m/s

When a sprinter is running a 100m sprint race. The race begins, and the stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, then the sprinter's average velocity between the two-time marks would be

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. The velocity of an object depends on the magnitude as well as the direction of the object.

the mathematical expression for velocity is given by

velocity = total displacement /time

As given in the problem a sprinter is running a 100m sprint race. The race begins, and the stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s

The total displacement covered by the sprinter

S = 59-12

S= 47 m

The total time is taken by the sprinter

T= 7.98 -1.92

 = 6.06 seconds

Velocity = S/T

             =47/6.06

             =7.75 m/s

Thus. the average velocity of the sprinter would be 7.75 m/s

Learn more about Velocity from here

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