Answer:
After three hours, concentration of C₂F₄ is 0.00208M
Explanation:
As the units of the rate constant of the reaction are M⁻¹s⁻¹ we can know this reaction is of second order. Its integrated law is:
[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +Kt[/tex]
Where [A] and [A]₀ represents initial and final concentrations of the reactant (C₂F₄), K is rate constant (0.0410M⁻¹s⁻¹) and t is time.
3.00 hours are in seconds:
3 hours ₓ (3600 seconds / 1 hour) = 10800 seconds
Computing in the equation:
[tex]\frac{1}{[A]} =\frac{1}{[0.105mol / 4L]} +0.0410M^{-1}s^{-1}*10800s\\\frac{1}{[A]} = 480.9M^{-1}\\\[/tex]
[A] = 0.00208M
