Answer:
[tex](B.) y= 1/2x -3/2[/tex]
Step-by-step explanation:
[tex](-3, -3) = (x_1,y_1)\\m = 1/2\\\\y-y_1=m(x-x_1)\\\\y -(-3)=\frac{1}{2} (x -(-3)\\\\y+3 = \frac{1}{2}(x+3)\\\\ y+3 = \frac{1}{2} x+\frac{3}{2}\\\\ y = \frac{1}{2} x +\frac{3}{2} -3\\\\y = \frac{1}{2} x - \frac{3}{2}[/tex]
Answer:
[tex]\Large \boxed{\mathrm{Option \ B}}[/tex]
Step-by-step explanation:
y = mx + b
(slope intercept form of a line)
m = slope
b = y-intercept
y = 1/2x + b
Only three options have a slope of 1/2.
y= 1/2x + 3/2
y= 1/2x - 3/2
y= 1/2x - 1/2
The line crosses the point (-3, -3), x = -3 and y = -3.
-3= 1/2(-3) + 3/2
-3= -3/2 + 3/2
-3 = 0
This is false.
-3= 1/2(-3) - 3/2
-3 = -3/2 - 3/2
-3 = -6/2
-3 = -3
This is true.
-3= 1/2(-3) - 1/2
-3 = -3/2 - 1/2
-3 = -2
This is false.
