Answer:
1.2 mL
Explanation:
This is a problem of simple dilution. The dilution principle simply agrees that the number of moles before dilution must be equal to the number of moles after dilution.
Recall that: number of moles = mass/molar mass or molarity x volume.
Hence, for the dilution principle:
initial molarity x initial volume = final molarity x final volume.
In this case, initial molarity of NaOH = 1 M, initial volume = ?, final molarity = 0.1 M, final volume = 12.0 mL.
Initial volume = final molarity x final volume/initial molarity
= 0.1 x 12/1 = 1.2 mL
It thus means that 1.2 mL of 1 M NaOH would be taken and then diluted up to 12.0 mL mark by the addition of distilled water in order to produce 12.0 mL, 0.10 M NaOH solution.
The volume should be 1.2 mL
It should be agreed that the no of moles prior to the dilution should be equivalent to the no of moles after dilution
We know that
number of moles = mass / molar mass or molarity x volume.
According to the above principle, we can say that
initial molarity x initial volume = final molarity x final volume.
So,
initial molarity of NaOH = 1 M,
initial volume = ?,
final molarity = 0.1 M,
And, final volume = 12.0 mL.
So,
Initial volume = final molarity x final volume/initial molarity
= 0.1 x 12/1
= 1.2 mL
Hence, The volume should be 1.2 mL
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