Answer:
The force is [tex]F = 21.48 \ N[/tex]
Explanation:
From the question we are told that
The diameter of the wire is [tex]d = 1.5 \ mm = 1.5 *10^{-3} \ m[/tex]
The pressure is [tex]P = 120 \ a.t.m = 120 * 101.3 *10^{3} = 12156000 Pa[/tex]
Generally the radius of the of the wire is
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{ 1.5 *10^{-3}}{2}[/tex]
=> [tex]r = 7.5 *10^{-4} \ m[/tex]
The Area is evaluated as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * 7.5 *10^{-4}[/tex]
=> [tex]A = 1.7673*10^{-6} \ m^2[/tex]
Generally pressure is mathematically represented as
[tex]P = \frac{F}{A }[/tex]
=> [tex]F = P* A[/tex]
=> [tex]F = 12156000 * 1.767*10^{-6}[/tex]
=> [tex]F = 21.48 \ N[/tex]
