Answer:
The radius is [tex]R = 0.22 5 \ m[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 61 \ A[/tex]
The magnetic field is [tex]B = 1.70 *10^{-4} \ T[/tex]
Generally the magnetic field produced by a current carrying conductor is mathematically represented as
[tex]B = \frac{\mu_o * I}{2 * R }[/tex]
=> [tex]R = \frac{\mu_o * I }{ 2 * B }[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]R = \frac{ 4\pi * 10^{-7} * 61 }{ 2 * 1.70 *10^{-4} }[/tex]
=> [tex]R = 0.22 5 \ m[/tex]
