Respuesta :

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

C = 0.45 J/g･°C

Heat involved,

q =  801 J

Temperature,

ΔT = 120.0°C-22.5°C

     = 97.5°C

As we know,

⇒  [tex]C = \frac{q}{m \Delta T}[/tex]

On substituting the given values, we get

⇒  [tex]0.45=\frac{801}{m(97.5)}[/tex]

⇒  [tex]m = 18.25 \ g[/tex]

Lanuel

The mass in grams of iron heated during the change in temperature is 18.26 grams.

Given the following data:

  • Initial temperature = 22.5°C
  • Final temperature = 120.0°C
  • Quantity of heat = 801 Joules
  • Specific heat capacity of iron = 0.45 J/g°C.

To find the mass in grams of iron heated during the change in temperature:

Mathematically, quantity of heat is given by the formula;

[tex]Q = mc\theta[/tex]

Where:

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Making mass (m) the subject of formula, we have:

[tex]Mass = \frac{Q}{c \theta}[/tex]

Substituting into the formula, we have:

[tex]Mass = \frac{801}{0.45(120\;-\;22.5)} \\\\Mass = \frac{801}{0.45(97.5)} \\\\Mass = \frac{801}{43.875}[/tex]

Mass, m = 18.26 grams.

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