Answer:
[tex]\huge \boxed{\mathrm{0.65 \ in^2}}[/tex]
Step-by-step explanation:
Area of square = [tex]s^2[/tex]
[tex]0.5^2 = 0.25[/tex]
Area of triangle = [tex]\frac{bh}{2}[/tex]
[tex]\frac{0.5 \times 0.4}{2}=0.1[/tex]
The surface area of the net = area of square + 4(area of triangle)
[tex]0.25+4(0.1)=0.65[/tex]
