Answer:
2.15
Explanation:
For this question, we have to remember the pH formula:
[tex]pH~=~-Log[H_3O^+][/tex]
By definition, the pH value is calculated when we do the -Log of the concentration of the hydronium ions ([tex]H_3O^+[/tex]). So, the next step is the calculation of the concentration of the hydronium ions. For this, we have to use the molarity formula:
[tex]M=\frac{mol}{L}[/tex]
We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:
[tex]M=\frac{0.0231~moles}{3.33~L}=0.00693~M[/tex]
With this value, now we can calculate the pH value:
[tex]pH~=~-Log[0.00693~M]~=~2.15[/tex]
The pH would be 2.15
I hope it helps!
