Answer:
[tex]A=1158.66\ \text{inches}^2[/tex]
Step-by-step explanation:
Given that,
The diameter of the base of a circular cone, d = 18 inches
Height of the cone, h = 40 inches
We need to find the lateral surface area of the cone. The formula of the lateral surface of the cone is given by :
[tex]A=\pi rl[/tex]
l is the slant height of the cone,
[tex]l=\sqrt{r^2+h^2} \\\\l=\sqrt{(9)^2+(40)^2} \\\\l=41\ \text{inches}[/tex], d = 18 inches, r = 9 inches
So,
[tex]A=3.14\times 9\times 41\\\\A=1158.66\ \text{inches}^2[/tex]
So, the lateral surface area of the cone is [tex]1158.66\ \text{inches}^2[/tex].
