Answer:
The value is [tex]\eta = 0.2145[/tex] or 21.45%
Explanation:
From the question we are told that
The first reservoir is at steam point [tex]T_s = 100^o C = 100 + 273 = 373 \ K[/tex]
The second reservoir is at room temperature [tex]T_r = 20^o C = 293 \ K[/tex]
Generally the maximum theoretical efficiency of a Carnot engine is mathematically evaluated as
[tex]\eta = 1- \frac{T_r}{T_s}[/tex]
=> [tex]1 - \frac{ 293}{373}[/tex]
=> [tex]\eta = 0.2145[/tex]
