Answer:
Area = 3097.96[tex]m^{2}[/tex]
Perimeter = 270.96m
Step-by-step explanation:
Step 1: State the shapes making up the indoor sports exhibiti[tex]\pi[/tex]on
2 rectangles
1 semi circle
Step 2: Find the area and perimeter of the shapes
ARectangle1 = lw = (10)(40) = 400m^2
PRectangel1 = 2l + w = 2(10) + 40 = 60m
ARectangle2 = lw = (33)(68) = 2244m^2
PRectangel2 = l + w = 33 + 68 = 101m
ASemiCicle = [tex]\frac{\pi r^{2}}{2} =\frac{\pi 17^{2} }{2} =\frac{289\pi }{2}=144.5\pi=453.96m^{2}[/tex]
PSemiCircle = [tex]2\pi r=2\pi(17)=35\pi =109.96m[/tex]
Step 3: Add up the areas and perimeters
Area = 400 + 2244 + 453.96
Area = 3097.96[tex]m^{2}[/tex]
Perimeter = 60 + 101 + 109.96
Perimeter = 270.96m
Therefore the area of the indoor sports exhibition is 3097.96[tex]m^{2}[/tex] and the perimeter is 270.96 m
