Answer:
[tex] \boxed{ \bold{x = 4.54}}[/tex]
Step-by-step explanation:
[tex] \sf{Given}[/tex]
[tex] \sf{hypotenuse = 5}[/tex]
[tex] \sf{base = 2.1}[/tex]
[tex] \sf{perpendicular = x}[/tex]
Now, Let's find the value of x
Using Pythagoras theorem
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
Plug the values
⇒[tex] \sf{ {5}^{2} = {x}^{2} + {2.1}^{2} }[/tex]
Evaluate the power
⇒[tex] \sf{25 = {x}^{2} + 4.41}[/tex]
Swap the sides of the equation
⇒[tex] \sf{ {x}^{2} + 4.41 = 25}[/tex]
Move constant to R.H.S and change it's sign
⇒[tex] \sf{ {x}^{2} = 25 - 4.41}[/tex]
Calculate the difference
⇒[tex] \sf{ {x}^{2} = 20.59}[/tex]
Squaring on both sides
⇒[tex] \sf{x = 4.54}[/tex]
Hope I helped!
Best regards!!
