1. The temperature at which the volume of gas has been 960 ml is [tex]\rm \bold{19.99\;^\circ C}[/tex].
2. The temperature at which the volume of gas has been [tex]\rm 300\;cm^3[/tex] is [tex]\rm \bold{90^\circ C}[/tex].
1. The gas has been assumed to be an ideal gas. For an ideal gas, the relationship between temperature and volume at constant pressure has been given as:
[tex]\dfrac{V1}{T1}=\dfrac{V2}{T2}[/tex]
Where, the initial volume, [tex]V1=720\;\text {ml}[/tex]
The final volume, [tex]V2=960\;\text {ml}[/tex]
The initial temperature, [tex]T1=15\;^\circ \text C[/tex]
Substituting the values, the final temperature, T2 can be given as:
[tex]\rm \dfrac{720\;ml}{15\;^\circ C}=\dfrac{960\;ml}{\textit{T}2} \\\textit T2=\dfrac{15\;^\circ C}{720\;ml}\;\times\;960\;ml\\\textit T2=19.99\;^\circ C[/tex]
The temperature at which the volume of gas has been 960 ml is [tex]\rm \bold{19.99\;^\circ C}[/tex].
2. The temperature for gas to occupy [tex]\rm 300\;cm^3[/tex] has been given as:
Where, the initial volume, [tex]V1=900\;\rm{cm^3}[/tex]
The final volume, [tex]V2=300\;\rm {cm^3}[/tex]
The initial temperature, [tex]T1=270\;^\circ \text C[/tex]
Substituting the values, the final temperature, T2 can be given as:
[tex]\rm \dfrac{900\;cm^3}{270\;^\circ C}=\dfrac{300\;cm^3}{\textit{T}2} \\\textit T2=\dfrac{270\;^\circ C}{900\;cm^3}\;\times\;300\;cm^3\\\textit T2=90\;^\circ C[/tex]
The temperature at which the volume of gas has been [tex]\rm 300\;cm^3[/tex] is [tex]\rm \bold{90^\circ C}[/tex].
For more information about the volume of gas, refer to the link:
https://brainly.com/question/1218415
