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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Solve the equations for x and match the solutions.

Drag the tiles to the correct boxes to complete the pairs Not all tiles will be used Solve the equations for x and match the solutions class=

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akposevictor

Answer:

[tex] -ax - 20 = -14 [/tex] => [tex] x = -\frac{6}{a} [/tex]

[tex] 4 = \frac{6}{a}x + 5 [/tex] => [tex] x = -\frac{a}{6} [/tex]

[tex] 7 + 2ax = 13 [/tex] => [tex] x = \frac{3}{a} [/tex]

Step-by-step explanation:

[tex] -ax - 20 = -14 [/tex]

[tex] -ax - 20 + 20 = -14 + 20 [/tex]

[tex] -ax = 6 [/tex]

[tex] \frac{-ax}{-a} = \frac{6}{-a} [/tex]

[tex] x = -\frac{6}{a} [/tex]

[tex] 4 = \frac{6}{a}x + 5 [/tex]

[tex] 4 - 5 = \frac{6}{a}x + 5 - 5 [/tex]

[tex] - 1 = \frac{6}{a}x [/tex]

[tex] - 1*\frac{a}{6} = \frac{6}{a}x*\frac{a}{6} [/tex]

[tex] -\frac{a}{6} = x [/tex]

[tex] x = -\frac{a}{6} [/tex]

[tex] 7 + 2ax = 13 [/tex]

[tex] 7 + 2ax - 7 = 13 - 7 [/tex]

[tex] 2ax = 6 [/tex]

[tex] \frac{2ax}{2a} = \frac{6}{2a} [/tex]

[tex] x = \frac{3}{a} [/tex]

websitetechie

Your Answer:

A) -ax - 20 = -14 <-----> x = [tex]-\frac{6}{a}[/tex]

B) 4 = [tex]\frac{6}{a}x +5[/tex] <-----> x = [tex]-\frac{a}{6}[/tex]

C) 7 + 2ax = 13 <-----> x = [tex]\frac{3}{a}[/tex]

My Question:

Drag the tiles to the correct boxes. Not all tiles will be used.

Match each equation with a value of x that satisfies it.

[tex]\sqrt{x^{2}+7 } = 4[/tex] ---->

[tex](x-2)^{\frac{1}{4} } = 2[/tex] ---->

[tex]\sqrt[3]{1-x} = -1[/tex] ---->

My Answers:

In photo below

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