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14-08-2020
Chemistry

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In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 57.84 g of MgI₂ form, what is the percent yield?

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Leora03 Leora03

14-08-2020

Answer:

88.1% (to 3 s.f.)

Explanation:

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