Answer:
r₁₀ = 52.9 nm
Explanation:
In Bohr's model of the hydrogen atom, the radius of the orbitals can be written as a function of the radius of the first orbit
rₙ = n² a₀
where ao is 0.0529 nm and is the radius of the ground state of the atom
the radius for the excited state with n = 10
r₁₀= 10² a₀
r₁₀ = 100 a₀
r₁₀ = 52.9 nm
