Respuesta :
Answer: 1. 1,906,500
2. 840
Step-by-step explanation:
1. Given: There are 125 juniors at the high school.
Total positions = 3 [president,vice president, and secretary]
Then, Number of ways to elect a president,vice president, and secretary( which is in order) out of 125 juniors = [tex]^{125}P_{3}=\dfrac{125!}{(125-3)!}[/tex] [Using permutations]
[tex]=\dfrac{125!}{122!}\\\\=\dfrac{125\times124\times123\times122!!}{122!}\\\\=125\times124\times123\\\\=1906500[/tex]
Hence, Required ways =1906500
(2) Given word : "RHOMBUS"
Total letters= 7
By permutation, the umber of 4-letter arrangements = [tex]^7P_4=\dfrac{7!}{(7-4)!}=\dfrac{7!}{3!}[/tex]
[tex]=\dfrac{7\times6\times5\times4\times3!}{3!}\\\\= 7\times6\times5\times4\\\\=840[/tex]
Hence, required ways = 840
Answer:
1) The number of ways = 1906500.
2) The number of ways = 840.
1) President, vice president, and secretary are 3 different positions.
There are total 125 students.
So we can select them in [tex]125P3=\frac{125!}{\left(125-3\right)!}=1906500[/tex] ways.
2) There are total 7 different letters in RHOMBUS.
We can select 4 different letters from 7 letters in [tex]7P4=\frac{7!}{\left(7-4\right)!}=840[/tex].
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