if AB ll CD , EF ll BC, angle bac = 65 and angle dhf = 35 find angle agh

You know that AB is || to CD, angle BAC ≅ ACD (this is the theorem where a line connecting the diagnose of two parallel line, the alternative interior angles are equal/ congruent)

You know that EF is || to BC, angle DHF ≅ GHC (these two are vertically opposite angle which are equal/ this is a theorem)

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we now know the angles in ΔGHC where angle GHC=35, angle GCH=65, and angle CGH=80 (subtract other angles from 180)

angle AGH is supplementary w=angle with CGH, which means we subtract 80 from 180, we get 100 will be the angle of AGH

if AB ll CD , EF ll BC, angle bac = 65 and angle dhf = 35 find angle agh​

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if AB ll CD , EF ll BC, angle bac = 65 and angle dhf = 35 find angle agh