A car is going 8 meters per second on an access road into a highway
and then accelerates at 1.8 meters per second squared for 7.2
seconds. How fast is it then going?

Respuesta :

Answer:

20.96 m/s is the final speed.

Step-by-step explanation:

Given that:

Initial speed of the car = 8 m/s

Acceleration of the car = 1.8 m/[tex]s ^{2}[/tex]

Time for which the car accelerates = 7.2 seconds

To find:

The speed of car after accelerating for 7.2 seconds at an acceleration of 1.8 m/[tex]s ^{2}[/tex] = ?

Solution:

First of all, let us have a look the formula given for the final velocity of an object with given initial speed, acceleration and time:

[tex]v=u+at[/tex]

Where [tex]v[/tex] is the final speed of object

[tex]u[/tex] is the initial speed of an object

[tex]a[/tex] is the acceleration of object and

[tex]t[/tex] is the time

Here, [tex]u = 8\ m/s[/tex]

[tex]a = 1.8\ m/s^{2}[/tex] and

[tex]t = 7.2\ seconds[/tex]

To find:

[tex]v = ?[/tex]

Let us put all the given values in the formula:

[tex]v =8+1.8 \times 7.2\\\Rightarrow v =8+12.96\\\Rightarrow \bold{v =20.96\ m/s}[/tex]

So, the answer is:

20.96 m/s is the final speed.