Answer:
[tex]\large \boxed{\text{50 g Na}}[/tex]
Explanation:
We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
Mᵣ: 22.99
2NaCl ⟶ 2Na + Cl₂
Units: 1.3 × 10²⁴
1. Calculate the moles of NaCl
[tex]\text{Moles of NaCl}\\\\= 1.3 \times 10^{24} \text{ formula units NaCl} \times \dfrac{\text{1 mol NaCl}}{6.022 \times 10^{23}\text{ formula units NaCl}}\\\\= \text{2.16 mol NaCl}[/tex]
2. Calculate the moles of Na
The molar ratio is 2 mol Na:2 mol Na Cl
[tex]\text{Moles of Na} = \text{2.16 mol NaCl} \times \dfrac{\text{2 mol Na}}{\text{2 mol NaCl}} = \text{2.16 mol Na}[/tex]
3. Calculate the mass of Na
[tex]\text{Mass of Na} = \text{2.16 mol Na} \times \dfrac{\text{22.99 g Na}}{\text{1 mol Na}} = \textbf{50 g Na}\\\\\text{The reaction will form $\large \boxed{\textbf{50 g Na}}$}[/tex]
