Answer:
$4.84
Step-by-step explanation:
Given that
For delivery within [tex]1\frac{1}2[/tex] mi, charges = $1.25
For delivery within [tex]1\frac{1}2[/tex] mi - [tex]1\frac{3}4[/tex] mi, charges = $1.70
For delivery within [tex]1\frac{3}4[/tex] mi - 2 mi, charges = $2.15
and
so on.
i.e.
For delivery within 2 mi - 2[tex]\frac{1}4[/tex] mi, charges = $2.60
For delivery within 2[tex]\frac{1}4[/tex] mi - 2[tex]\frac{1}2[/tex] mi, charges = $3.05
For delivery within 2[tex]\frac{1}2[/tex] mi - 2[tex]\frac{3}4[/tex] mi, charges = $3.50
For delivery within 2[tex]\frac{3}4[/tex] mi - 3 mi, charges = $3.95
For delivery within 3 mi - 3[tex]\frac{1}4[/tex] mi, charges = $4.40
So, every 0.25 mi or [tex]\frac{1}4[/tex] mi increase in distance, there is an increase of $0.45 in the charges.
It is given that there is increase of 10% in the rates.
i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.
The distance of [tex]3\frac{1}8[/tex] miles lies within the range 3 mi - 3[tex]\frac{1}4[/tex] mi.
So actual charges after increase of 10%
[tex]\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}[/tex]