Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $1.25 for a delivery made within 1 1/2 mi, $1.70 for a delivery of at least 1 1/2 mi but less than 1 3/4 mi, $2.15 for a delivery of at least 1 3/4 mi but less than 2 miles, and so on. If tim raised his rates by 10% what would he be paid to deliver a package 3 1/8 miles

Respuesta :

Answer:

$4.84

Step-by-step explanation:

Given that

For delivery within [tex]1\frac{1}2[/tex] mi, charges = $1.25

For delivery within [tex]1\frac{1}2[/tex] mi - [tex]1\frac{3}4[/tex] mi, charges = $1.70

For delivery within [tex]1\frac{3}4[/tex] mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2[tex]\frac{1}4[/tex] mi, charges = $2.60

For delivery within 2[tex]\frac{1}4[/tex] mi - 2[tex]\frac{1}2[/tex] mi, charges = $3.05

For delivery within 2[tex]\frac{1}2[/tex] mi - 2[tex]\frac{3}4[/tex] mi, charges = $3.50

For delivery within 2[tex]\frac{3}4[/tex] mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3[tex]\frac{1}4[/tex] mi, charges = $4.40

So, every 0.25 mi or [tex]\frac{1}4[/tex] mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of [tex]3\frac{1}8[/tex] miles lies within the range 3 mi - 3[tex]\frac{1}4[/tex] mi.

So actual charges after increase of 10%

[tex]\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}[/tex]