Answer:
Step-by-step explanation:
Hello, please consider the following.
[tex]6x^2-8x+k=0\\\\\text{We compute the discriminant.}\\\\\Delta = b^2-4ac=8^2-4*6*k=8*8-8*3*k=8*(8-3k)[/tex]
And the we know that if the discriminant is
***** [tex]\Delta[/tex] < 0, meaning 8-3k<0, meaning
[tex]\boxed{k>\dfrac{8}{3}}[/tex]
then, there is no real solution.
***** [tex]\Delta = 0[/tex], meaning
[tex]\boxed{k=\dfrac{8}{3}}[/tex]
There is 1 solution.
***** [tex]\Delta[/tex] > 0, meaning
[tex]\boxed{k<\dfrac{8}{3}}[/tex]
There are 2 solutions.
Thank you
PS: To give more details...
[tex]8-3k=0\\\\\text{Add 3k}\\\\8=3k\\\\\text{Divide by 3}\\\\k=\dfrac{8}{3}[/tex]
