Answer:
Step-by-step explanation:
I'll use x instead of theta.
So we have:
sin x / ( 1 + cos x) + (1 +cos x) / sinx
The LCM is sin x(1 + cos x) so we have
sin^2 x + (1 + cos x)^2 / sin x(1 + cos x)
= sin^2 x + cos^2x + 2 cos x + 1 / sin x(1 + cos x)
Now sin^2x + cos^2x = 1 so:
= 2 + 2 cos x / sin x(1 + cos x)
= 2(1+ cos x) / sin x(1 + cos x)
The 1 + cos x is common so we have:
2 / sin x
= 2 cosec x.