On a coordinate plane, a curved line with minimum values of (negative 0.8, negative 2.8) and (3, 0), and a maximum value of (1.55, 10.8), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0). Which interval for the graphed function contains the local maximum? [–3, –2] [–2, 0] [0, 2] [2, 4]

Respuesta :

Answer:

(0,2)

Step-by-step explanation:

So C

The correct option is option C: [0,2] contains the local maximum.

What is the local maximum?

Local maximum is the relative maximum point where it is maximum within the neighborhood of that point.

From the graph shown in the picture, it is clear that,

the curved line touches the x axis at the point R(-2.5, 0), O(0, 0), and Q(3, 0).

similarly, the curved line touches the y-axis at O(0,0).

the graph has local minima at P(-0.8,-2.8) and Q(3, 0).

So the graph is below the x-axis between the point (-2.5, 0), (0, 0).

the graph has local maxima at S(1.55,10.8).

So the graph is above the x-axis between the point (0, 0), and (3, 0).

so the local maximum occurs at S(1.55,10.8).

From the option, it is clear that the point  (1.55,10.8) lies in the interval [0,2].

Therefore [0,2] contains the local maximum.

Learn more about local maximum

here: https://brainly.com/question/2193816

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