Answer: ∑Tₓ = 201.222
time required to complete the last two units is 201.222 minutes
Explanation:
Given that,
total time required to four units is 600 hours,
Learning curve applied is 75% and from the learning curve coefficient table, total time factor to complete four units at 75% learning curve is 2.946
so
∑Tₙ = T₁ × total time factor
{ ∑Tₙ is total time required to complete all the units which is 600 hrs, T₁ is Time for first unit, total time factor = 2.946 }
we substitute
∑T₄ = ∑T₁ × total time factor
600 = ∑T₁ × 2.946
∑T₁ = 600/2.946
∑T₁ = 203.666 minutes
Now to get the total time required to complete 6 units, we say:
∑T₆ = ∑T₁ × total time factor
Note that total time factor at this point changes;
( from the learning curve coefficient table, total time factor to complete 6 units at 75% learning curve is 3.934)
so we substitute
∑T₆ = 203.666 × 3.934
∑T₆ = 801.222
Now to find how long should it take them to finish the last two units, we say
∑Tₓ = ∑T₆ - ∑T₄
∑Tₓ = 801.222 - 600
∑Tₓ = 201.222
Therefore time required to complete the last two units is 201.222 minutes
The time required to complete the last two units is 201.222 minutes
Given data
Total time required to four units is 600 hours
Learning curve applied is 75% and 75% learning curve is 2.946
∑Tₙ = T₁ × total time factor
{ ∑Tₙ is total time required to complete all the units which is 600 hrs, T₁ is Time for first unit, total time factor = 2.946 }
we substitute
∑T₄ = ∑T₁ × total time factor
600 = ∑T₁ × 2.946
∑T₁ = 600/2.946
∑T₁ = 203.666 minutes
Now to get the total time required to complete 6 units, we say:
∑T₆ = ∑T₁ × total time factor
so we substitute
∑T₆ = 203.666 × 3.934
∑T₆ = 801.222
Now, we will find how long should it take them to finish the last two units
∑Tₓ = ∑T₆ - ∑T₄
∑Tₓ = 801.222 - 600
∑Tₓ = 201.222
In conclusion, the time required to complete the last two units is 201.222 minutes
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