Answer:
a. [tex]2.54 \times 10^{21} NC^{-1}[/tex]
b. Outwards
Explanation:
The computation is shown below:
a. The magnitude could be computed by applying the following formula
Electric field, E is
[tex]= \frac{kq}{r^{2}} \\\\ = \frac{9\times10^{9} \times86\times1.6\times10^{-19}}{(6.98\times10^{-15})^2}[/tex]
[tex]= 2.54 \times 10^{21} NC^{-1}[/tex]
b. As we can see that there is a positive charge so the direction would be in the outward direction in the electric field i.e. produced by the protons
Basically we applied the above formula for the first part
