Answer:
B. 2.7 g
Step-by-step explanation:
The half life of a substance is the time taken for the substance to reduce to half of its original amount. It is given by:
[tex]A=A_o*(\frac{1}{2})^\frac{t}{t_{1/2}}\\ Where\ A\ is \ the \ amount \ of \ substance\ remaining\ after\ t\ years, \\A_o \ is \ the\ initial\ value\ of \ the\ substance,\ t_{1/2} is\ the\ half\ life\ and\\t\ is\ the\ years\ spent[/tex]
Given that:
Ao = 4 g, t = 3 years, t(1/2) = 5.26 years. Therefore:
[tex]A=A_o*(\frac{1}{2})^\frac{t}{t_{1/2}}\\A=4*(\frac{1}{2} )^\frac{3}{5.26}=4*0.6735=2.7\\ A=2.7\ g[/tex]
