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Human lungs have evolved to breathe oxygen at a pressure as that in the atmosphere, 0.21 atm. If a particular heliox mixture to be carried by a scuba diver is at a pressure of 7.00 atm, what should be the partial pressure due to helium in order to maintain the pressure due to oxygen at 0.21 atm?

Respuesta :

Oseni

Answer:

6.79 atm

Explanation:

Applying Dalton's law of partial pressure:

[tex]P_{total} = P_{helium} + P_{oxygen}[/tex], where [tex]P_{total}[/tex] = total partial pressure of all the component gases in the mixture, [tex]P_{helium}[/tex] = partial pressure of helium gas, and [tex]P_{oxygen}[/tex] = partial pressure of oxygen gas.

From the illustration, [tex]P_{total}[/tex] = 7.00 atm and [tex]P_{oxygen}[/tex] = 0.21 atm. Hence, the partial pressure due to helium is calculated such that:

[tex]P_{helium}[/tex] = [tex]P_{total} - P_{oxygen}[/tex]

           = 7.00 - 0.21

              = 6.79 atm

Therefore, the partial pressure due to helium in order to maintain the pressure due to oxygen at 0.21 atm would be 6.79 atm.

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