Suppose an experimenter becomes proficient with a technique that allows her to move DNA sequences within a prokaryotic genome. If a researcher moves the repressor gene (lacI), along with its promoter, to a position at some several thousand base pairs away from its normal position, which of the following results would be expected?
A) The repressor will no longer bind to the operator.
B) The repressor will no longer bind to the inducer.
C) The lac operon will be expressed continuously.
D) The lac operon will function normally.

The promoter area can be described as the area that causes the transcription to initiate for a particular gene. Promoters may be near the genes from which they initiate transcription or they may display multiple scenes upstream.
The lock operon works normally because the promoter area can still enable transcription on many base pairs. Detects repression promoter and works normally.
so correct option is D) The lac operon will function normally.

priyankatutor priyankatutor · Answer 2 · 2021-12-08T07:26:41+01:00

If a researcher moved the repressor gene of lac I, along with its promoter; the lac operon will function normally. Option D is correct.

Promotor:

It is the genetic sequence that is recognized by the RNA polymerase to start the transcription.

Here, researcher moved the repressor gene of lac I , along with its promoter.

Therefore, transcription starts, it will express the repressor gene also because repressor gene was moved with promotor.

To know more about Lac operon,

https://brainly.com/question/4109690