Hey there please help me with this question
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Answer:
see explanation
Step-by-step explanation:
sum the parts of the ratio, 2 + 1 = 3 parts , thus
81 cm² ÷ 3 = 27 cm² ← value of 1 part of the ratio
2 parts = 2 × 27 = 54 cm²
Area of A = 54 cm² and area of B = 27 cm²
The side of the original square = [tex]\sqrt{81}[/tex] = 9 cm
The width of both rectangles is 9 cm ( width remains unchanged after cut )
Thus
Rectangle A
9 × length = 54 ( divide both sides by 9 )
length = 6 cm
Rectangle B
9 × length = 27 ( divide both sides by 9 )
length = 3 cm
Rectangle A → length = 6 cm, width = 9 cm
Rectangle B → length = 3 cm , width = 9 cm
Answer:
Rectangle A Rectangle B
length = 9 cm length = 9 cm
width = 6 cm width = 3 cm
Step-by-step explanation:
Area of square At = 81 cm²
Square is cut into two pieces = A + B
The ration of area A to B = 2:1
Find
Rect A Rect B
length length
width width
---------------------------------
first, get the side of the square = A = s²
81 = s²,
s = √81
s = 9 cm
since the ratio is 2:1, therefore the side can be divided into 3
9 ÷ 3 = 3 cm ----- take note of this to get the Width
Rectangle A
L = 9 cm (which is the s = 9 cm)
W = 3 cm (2 ratio) = 6 cm
Rectangle B
L = 9 cm (which is the s = 9 cm)
W = 3 cm (1 ratio) = 3 cm
Proof:
At = A + B
81 = (9x6) + (9x3)
81 = 54 + 27
81 = 81 ----- OK