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The area of a trapezium is 105cm² and its height is 7 cm. If one of the parallel sides is longer than the other by 6cm, find the lengths of two parallel sides.

Respuesta :

Area of trapezium [tex] =\frac{h(a+b)}{2}[/tex]

Given: $h=7$ and say, $a>b$ So, $a=b+6$

$105=\frac{7(2b+6)}{2}$

$15=b+3$

$b=12$

$a=18$

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