Answer:
Step-by-step explanation:
We first need to find h. Since h is the x coordinate of Q, and Q is on the line 3x + 4y = 6, we will plug in the x value of h and the y value of 3 and solve for h:
3h + 4(3) = 6 and
3h + 12 = 6 and
3h = -6 so
h = -2
The coordinates for Q are (-2, 3). Now we can use that to find the slope of the line QR:
[tex]m=\frac{8-3}{3-(-2)}=\frac{5}{5}=1[/tex]
So the slope of QR is 1. Now we will choose one of the coordinates on line QR as our x and y coordinates to write the equation for the line in point slope form then in standard form:
y - 8 = 1(x - 3) and
y - 8 = x - 3 and
y - x = 5 or
-x + y = 5. If your teacher does not want you to lead with a negative:
x - y = -5 would be your equation in standard form.
