shirazlatif11 shirazlatif11

15-07-2020
Mathematics

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How many complex and real roots are in the problem (x+10)^9.

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wegnerkolmp2741o wegnerkolmp2741o

15-07-2020

Answer:

9 roots

Step-by-step explanation:

(x+10)^9 = 0

If you would multiply it out, the highest power is x^9 so the equation has 9 roots

Solving (x+10)^9 =0

Taking the 9th root of each sdie

x+10 = 0

x = -10

The root is -10 with multiplicity of 9

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