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ILL MARK BRAINLIEST PLS HELP

4. A student performs Young's double-slit experiment using a slit separation of 21.6 um. A
screen is placed 2.50 m from the centre of the sources such that a point on the fifth
nodal line is 37.5 cm from the centre of the interference pattern. Find the wavelength of
the light used and identify its colour.

Respuesta :

Answer:

[tex]\lambda=648\,\,nm[/tex]

which corresponds to red color

Explanation:

Recall that the formula for the maximum condition of interference when light of wave length [tex]\lambda[/tex] , for slit separation d, screen distance D, displacement from the center line y, and order m is given by:

[tex]y=\frac{m\,\lambda\,D}{d}[/tex]

So in our case, d = 21.6 micrometers, D = 2.5 m, y = 0.375 m, m = 5, and [tex]\lambda[/tex] is the unknown we solve for:

[tex]y=\frac{m\,\lambda\,D}{d}\\0.375\,\,m = \frac{5\,\lambda\,(2.5)}{21.6\,10^{-6}}\\\lambda=\frac{0.375\,*\,21.6\,\,10^{-6}}{5\,*\,2.5} \\\lambda=648\,\,nm[/tex]

And this wavelength corresponds to the red color (between about 625 nm and 740 nm)