The equation for the period of a pendulum is T=2 Square Root of L/g.
How does your equation from 1B relate to the pendulum equation?
Use the pendulum equation to calculate the period of a 1.50 m pendulum. Remember that the value of "g" is 9.81 m/s2.
Compare your calculated period (from 3B) to your data by using the graph you constructed. Explain any possible sources for error if your graph does not agree with your calculated results.

In this exercise we have the response of a simple pendulum consisting of a ball supported by an inextensible thread of negligible mass, the period of this system for small oscillations is

T = 2π √L/g

indicate that the length of the pendulum is L = 1.50 m

let's calculate the period

T = 2π √ (1.50 / 9.81)

T = 2.457 s

It asks us to compare with the value found in a graph, in general in simple pendulum experiments the constructed graph is T2 against L, which gives us a line and from which the equation of the line with the slope and the point of cut, in this equation the length is entered and the period is calculated.

In many cases the values found by the two methods are similar, but not the same, this is due to errors in time measurements, the most common are

* launch the pendulum from slightly different points

* reaction time when switching the timer on and off

* errors in reading the points for calculating the graph.